Sophia and Tyler are running around a 400-meter track. They start running from the same place, at the same time. Sophia runs at a speed of 5 m/s and Tyler runs at a speed of 4 m/s. How long will it take Sophia to lap Tyler?
Accepted Solution
A:
We will call:
S: Runner Sophia. T: Runner Tyler.
At the beginning the distance between both runners is 400m
At t = 1s Sophia runs 5m and Tyler 4m At t = 2s Sophia runs 10m and Tyler 8m
and so on.
So, for example at t = 1s, the distance between both runner is:
D = 400m - 5m(the advantage of Sophia) + 4m(what Tyler recovers)
So, we can find a general equation for this matter. Knowing that the distance, velocity and time are related by this equation:
[tex]d=vt[/tex]
Then, the distance between both runners, at any time, is given by:
[tex]D = 400-5t+4t[/tex]
So we need to find the how long it will take Sophia to lap Tyler. This happens when D = 0: