MATH SOLVE

2 months ago

Q:
# The area of a rectangle is (x^4+4x^3+3x^2-4x-4),and the length of the rectangle is (x^3+5x^2+8x+4). if the area = length x width, what is the width of the rectangle

Accepted Solution

A:

W = A/L

W = (x^4+4x^3+3x^2-4x-4) / (x^3+5x^2+8x+4)

W = x - 1

W = (x^4+4x^3+3x^2-4x-4) / (x^3+5x^2+8x+4)

W = x - 1